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9x^2+54x-40=0
a = 9; b = 54; c = -40;
Δ = b2-4ac
Δ = 542-4·9·(-40)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-66}{2*9}=\frac{-120}{18} =-6+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+66}{2*9}=\frac{12}{18} =2/3 $
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